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The Solar System's Manifestation of Planck Mass and Proton Mass

A. Nudelman

Abstract

It is well known that the average distances of the planets from the Sun are quantized according to the law: $2^1, 2^2, 2^3, \dots$. This law was established by Titius and Bode in the second half of the 18th century (this law has no strict scientific explanation to this day).

The average distance of a planet from the Sun ($L_{\!_R}$) is the radius of its orbit. The necessary calculations are made and we indicate (discover) two more laws in the Solar System (the calculations consider the mass of a planet, its orbital velocity $V_{pl}$ and the product $V_{pl}$ $L_{\!_R}$): the ratio of the densities of all the planets (and the density of the Sun) can be represented as such integers $1, 2, 3, 6, 8$ (the density of the Sun corresponds to 2); for all planets the product $V_{pl}L_R$ quantized (according to the sequence of integers $3,4,5,6,11,15,21,26,30$).

We establish that the main parameters of the Solar System are quantized; while $\boldsymbol{m_P / m_p}$ and $\boldsymbol{m_p / m_P}$ are special (key) ratios in this cosmic object.

1. Introduction

As is well known, M. Planck, in 1899, found a formula describing a certain special mass [1]. In this formula he used three physical constants: the constant $\hbar$, the gravitational constant $G$ and the speed of light in a vacuum $c$. Subsequently, this mass was named Planck mass and was accordingly denoted by $m_{{\!}_P} (m_{{\!}_P}=2.1767\cdot 10^{-5}\si{\gram}$).

For comparison, we indicate the mass of a proton $m_p$: $m_p=1.6726\cdot 10^{-24}\si{\gram}$. Next we show that the dimensionless parameter $m_{{\!}_P} / m_p$, as well as the parameter $m_p / m_{{\!}_P}$, are special quantitative parameters of the Solar System.

2. Quantization in the Solar System—distances and masses

2.1.1 Let us present some well-known data on the Solar System. This data is concentrated in two tables—1 and 2 (data—NASA [2, 3]). The data in the tables, as well as all calculations, are presented (performed) in the CGS system ($\si{\cm}$, $\si{\gram}$, $\si{\sec}$).

2.1.2 Table 1 shows the diameters of the planets, the average distances of the planets from the Sun, and the average velocities of the planets around the Sun.

Table 2 shows the masses of the planets and the Sun, as well as the density of these space objects.

Table 1: Diameters of the planets, distances of the planets from the Sun, and their orbital velocities.
Planet Diameter
$\boldsymbol{(10^8 \mathrm{cm})}$
Distance from Sun
$\boldsymbol{(10^{11} \mathrm{cm})}$
Orbital velocity
$\boldsymbol{(10^5 \mathrm{cm/sec})}$
1. Mercury 4.879 57.9 47.4
2. Venus 12.104 108.2 35.0
3. Earth 12.756 149.6 29.8
4. Mars 6.792 227.9 24.1
5. Jupiter 142.984 778.6 13.1
6. Saturn 120.536 1433.5 9.7
7. Uranus 51.118 2872.5 6.8
8. Neptune 49.528 4495.1 5.4
9. Pluto 2.370 5906.4 4.7

We will denote the orbital velocity of a planet (the average velocity of a planet as it orbits the Sun) by $V_{pl}$

Table 2: Mass and density of the planets and the Sun.
Planets and Sun Mass of space object $\boldsymbol{(10^{27} \mathrm{g})}$ Density of space object $\boldsymbol{(\mathrm{g/cm^3})}$
1. Mercury 0.33 5.427
2. Venus 4.87 5.243
3. Earth 5.97 5.514
4. Mars 0.642 3.933
5. Jupiter 1898 1.326
6. Saturn 568 0.687
7. Uranus 86.8 1.271
8. Neptune 102.0 1.638
9. Pluto 0.0146 2.095
10. Sun $1988.5 \cdot 10^{30}\mathrm{g}$ 1.408

2.2.1 If we examine quantization in the Solar System, then first of all it is necessary to point out the peculiarity of distances in this cosmic system. This feature is described by the well-known Titius–Bode law (calculation) [4, 5]. The Titius–Bode law (calculation) has existed for more than 200 years (it was established by Titius, and then slightly modified by Bode); it considered the planets that were known at that time (1766–1772).

2.2.2 According to this law (calculation), the average radii of the orbits along which the planets move, that is, the average distances of the planets from the Sun, are quantized by a certain macro-unit. This macro-unit is $1/8$ the distance from the Sun to Mercury; it is equal to $7.24 \cdot 10^{11} \si{\cm}$.

2.2.3 Table 3 shows the above-mentioned calculations—according to Titius–Bode—of the distance of a planet from the Sun (we denote it by $L_{{\!}_R}$)

Table 3: Calculations of $L_{\!_R}$ according to Titius–Bode.
Planet Calculation of $\boldsymbol{L_{{\!}_R}}$
(results are expressed in macro-units)
Calculated distance
$\boldsymbol{(10^{11} \mathrm{cm})}$
Actual distance
$\boldsymbol{(10^{11} \mathrm{cm})}$
1. Mercury ${8\phantom{+3 \cdot 2^15}=}{ \phantom{000}8}$ 57.9 57.9
2. Venus ${8+3 \cdot 2^1=}{ \phantom{00}14}$ 101.4 108.2
3. Earth ${8+3 \cdot 2^2 =}{ \phantom{00}20}$ 144.8 149.6
4. Mars ${8+3 \cdot 2^3 =}{ \phantom{00}32}$ 231.7 227.9
5. Jupiter ${8+3 \cdot 2^5 =}{ \phantom{0}104}$ 753.0 778.6
6. Saturn ${8+3 \cdot 2^6 =}{ \phantom{0}200}$ 1448.0 1433.5
7. (Uranus) ${8+3 \cdot 2^7=}{ \phantom{0}392}$ 2838.1 2872.5
8. (Neptune) ${8+3 \cdot 2^8 =}{ \phantom{0}776}$ 5618.2 4495.1
9. (Pluto) ${8+3 \cdot 2^9 =}{ 1544}$ 11178.6 5906.4

2.2.4 Note that the actual distances from the Sun to the planets Neptune and Pluto do not correspond to the Titius–Bode law (calculation).

2.3.1 Let us explore the masses of the cosmic objects that make up the Solar System. Let us assume that quantization should manifest itself not only in the distances of the planets from the Sun, but also in the masses of the planets (as well as in the mass of the Sun).

Let us exclude the influence of the sizes (radii) of the planets and the Sun on the magnitude of the masses under study. We examine not the entire volume of each space object, but only a part of the volume—$1 \si{\km^3}$ (that is, the density of the planets and the Sun).

2.3.2 If the masses of these space objects are quantized, then there must be a corresponding macro-unit of mass. After analyzing the data presented in Table 2, we found that such a macro-unit is the mass of $1\si{\km^3}$ of the volume of Saturn. This is the smallest of the unit masses (namely, the masses of volume $1\si{\km^3}$) among all considered objects of the Solar System. It is equal to $0.687 \cdot 10^{15}\si{\gram}$.

2.3.3 Let us present the results of the calculations (see table 4)

Table 4: Quantization of densities of the planets and the Sun.
Planets and Sun Mass of $\boldsymbol{1 \mathrm{km^3}}$ of planets and Sun
(expressed in grams) $\boldsymbol{10^{15}\mathrm{g}}$ (expressed in macro-units) (expressed in whole macro-units)
1. Mercury 5.427 7.90 ~ 8 Planet group А
2. Venus 5.243 7.63 ~ 8
3. Earth 5.514 8.03 ~ 8
4. Mars 3.933 5.73 ~ 6

5. Jupiter 1.326 1.93 ~ 2 Planet group B
6. Saturn 0.687 1.00 1
7. Uranus 1.271 1.85 ~ 2
8. Neptune 1.638 2.38 ~ 2
9. Pluto 2.095 3.05 ~ 3
10. Sun 1.408 2.05 ~ 2

2.3.4 We state: the masses of $1 \si{\km^3}$ of the volume of each planet and the Sun are quantized. Here are the indicated masses (expressed in whole macro-units) in order of increasing their magnitude: $1,2,2,2,2,3,6,8,8,8$

3. The Sun and the planets are one whole cosmic object

3.1.1 As noted in Section 1, Planck, considering together the three fundamental physical constants (the constant $\hbar$, the gravitational constant $G$ and the speed of light in vacuum $c$), obtained an expression describing some fundamental mass [1]. This mass was called the Planck mass and was denoted by $m_{{\!}_P}$ \begin{align*}\tag{1} m_{{\!}_P}=\left(\frac{\hbar c}{G} \right)^{\frac{1}{2}} \end{align*}

3.1.2 Let us introduce a nominal, hypothetical object that we will call a graton with the following definition (within the framework of this work):

a graton is a collection of molecules and/or atoms and/or elementary particles that has a total mass equal to the Planck mass. Each such collection can be interpreted as a certain physical object.
We denote the mass of a graton by $m_{\pi}$; while \begin{align*} m_{\pi} \equiv m_{{\!}_P}; \quad m_{\pi}=2.1767\cdot10^{-5}\si{\gram} \end{align*}

3.2.1 Let us explore the mass of the Sun, which we will denote by $\widetilde{M}$. Let us correlate the mass $\widetilde{M}$ with mass $m_{\pi}$ \begin{align*} \frac{\widetilde{M}}{ {m_{\pi}} } = \frac{1988.5\cdot 10^{30}}{2.1767\cdot 10^{-5}} = 0.914 \cdot 10^{38} \end{align*}

3.2.2 Let us transform the result we have obtained. Let us write it like this: \begin{align*}\tag{2} \widetilde{M}=(0.956\cdot 10^{19})^2 m_{\pi} \cong (10^{19})^2 m_{\pi} \end{align*}

According to the obtained expression, the Sun can (hypothetically) be divided into ${(10^{19})}^{2}$ gratons.

3.3.1 In Section 2, we showed the quantization of the following main parameters of the Solar System:

  • the distances of planets (averaged) from the Sun (Table 3);
  • the masses of $1 \si{\km}^3$ of each planet, as well as the Sun (Table 4).

3.3.2 There is one more main parameter—the orbital velocity of the planet (averaged). This parameter was denoted by $V_{pl}$ in Section 2; we will study it not separately, but as part of the following complex parameter: angular momentum (corresponding to each planet)—$\bar{m}V_{pl} L_{{\!}_R}$.

3.3.3 The values of the parameters $V_{pl}$ and $L_{{\!}_R}$ are given in Table 1 ($L_{{\!}_R}$ is the average distance of the planets from the Sun). Parameter $\bar{m}$ must be selected; the mass $\bar{m}$ can be selected as:

  • the mass of the entire planet (according to Table 2)—option I;
  • the mass of $1 \si{\km}^3$ of the planet's volume (according to Table 4)—option II;
  • the mass of a certain group of $S$ gratons—option III.

3.3.4 Options I and II cannot be accepted. The mass of the entire planet (option I) and the mass of $1 \si{\km}^3$ of the volume of each planet (option II) have different values for different planets. This means that the angular momenta of the planets will be incomparable (due to different values $\bar{m}$). Consequently, it will be impossible to establish the quantization (or lack of quantization) of the orbital velocities of the planets.

3.3.5 Let us move on to option III. A group of $S$ gratons will have the same mass for any planet (assuming $S = const$). For a fundamental solution to the problem posed, it is necessary and sufficient to consider only one graton (namely, we can assume that $S = 1$). We will examine the angular momenta of the unit corresponding to one or another planet—according to the formula \begin{align*}\tag{3} m_{\pi}V_{pl} L_{{\!}_R}; \end{align*} moreover, the nominal, hypothetical object (graton) under consideration must be located in the region of the center of mass of each planet.

3.3.6 The above calculations are presented in Table 5.

Table 5: Calculation of angular momenta of the unit.
Planet Angular momentum of the unit
Calculation Result $\boldsymbol{[m_{\pi}(\mathrm{cm^2} \cdot \mathrm{\sec^{-1}})]}$
1. Mercury $m_{\pi}[(47.4 \cdot 10^{5} \mathrm{cm/\sec})(57.9 \cdot 10^{11} \mathrm{cm})]$ $m_{\pi}[2.744 \cdot 10^{19}]$
2. Venus $m_{\pi}[(35.0 \cdot 10^{5} \mathrm{cm/\sec})(108.2 \cdot 10^{11} \mathrm{cm})]$ $m_{\pi}[3.787 \cdot 10^{19}]$
3. Earth $m_{\pi}[(29.8 \cdot 10^{5})(149.6 \cdot 10^{11} )]$ $m_{\pi}[4.458 \cdot 10^{19}]$
4. Mars $m_{\pi}[(24.1 \cdot 10^{5})(227.9 \cdot 10^{11})]$ $m_{\pi}[5.492 \cdot 10^{19}]$
5. Jupiter $m_{\pi}[(13.1 \cdot 10^{5})(778.6 \cdot 10^{11})]$ $m_{\pi}[10.200 \cdot 10^{19}]$
6. Saturn $m_{\pi}[(9.7 \cdot 10^{5})(1433.5 \cdot 10^{11})]$ $m_{\pi}[13.905 \cdot 10^{19}]$
7. Uranus $m_{\pi}[(6.8 \cdot 10^{5})(2872.5 \cdot 10^{11} )]$ $m_{\pi}[19.533 \cdot 10^{19}]$
8. Neptune $m_{\pi}[(5.4 \cdot 10^{5})(4495.1 \cdot 10^{11} )]$ $m_{\pi}[24.273 \cdot 10^{19}]$
9. Pluto $m_{\pi}[(4.7 \cdot 10^{5})(5906.4 \cdot 10^{11} )]$ $m_{\pi}[27.760 \cdot 10^{19}]$

3.4.1 Let us present the numerical results written above in square brackets in an approximate form (without the repeating factor $10^{19}$): \begin{align*} 2.7; \: 3.8; \: 4.5; \: 5.5;\: 10.2;\: 13.9;\: 19.5;\: 24.3;\: 27.8 \end{align*}

3.4.2 After analyzed these approximate results, we come to the conclusion that an additional dimensionless factor—coefficient $\bm{1.08}$, should be introduced into the calculations presented in Table 5. This coefficient takes into account what is associated with the ellipticity of the orbits along which the planets move around the Sun.

3.4.3 New (refined) values of the angular momenta of the unit—using the factor $1.08$, but without specifying units, are given in Table 6.

Table 6: Refined calculated values of angular momenta of the unit.
Planet Angular momentum of the unit
Calculation No parameter $\boldsymbol{m_{\pi}}$
Calculated value of $\boldsymbol{N}$ Same value expressed in integers
1. Mercury $m_{\pi}(2.744 \cdot 10^{19} ) \cdot 1.08$ $ 2.963 \cdot 10^{19}$ $\sim 3\cdot 10^{19}$
2. Venus $m_{\pi}(3.787 \cdot 10^{19} ) \cdot 1.08$ $4.090 \cdot 10^{19}$ $\sim 4\cdot 10^{19}$
3. Earth $m_{\pi}(4.458 \cdot 10^{19}) \cdot 1.08$ $4.815 \cdot 10^{19}$ $\sim 5\cdot 10^{19}$
4. Mars $m_{\pi}(5.492 \cdot 10^{19}) \cdot 1.08$ $5.931 \cdot 10^{19}$ $\sim 6\cdot 10^{19}$
1, 2, 3, 4 — group of planets A
5. Jupiter $m_{\pi}(10.200 \cdot 10^{19}) \cdot 1.08$ $11.016 \cdot 10^{19}$ $\sim 11\cdot 10^{19}$
6. Saturn $m_{\pi}(13.905 \cdot 10^{19}) \cdot 1.08$ $15.017 \cdot 10^{19}$ $\sim 15\cdot 10^{19}$
7. Uranus $m_{\pi}(19.533 \cdot 10^{19}) \cdot 1.08$ $21.096 \cdot 10^{19}$ $\sim 21\cdot 10^{19}$
8. Neptune $m_{\pi}(24.273 \cdot 10^{19}) \cdot 1.08$ $26.215 \cdot 10^{19}$ $\sim 26\cdot 10^{19}$
9. Pluto $m_{\pi}(27.760 \cdot 10^{19}) \cdot 1.08$ $29.981 \cdot 10^{19}$ $\sim 30\cdot 10^{19}$
5, 6, 7, 8, 9 — group of planets B

The obtained results can be described as follows (taking into account formula (3)) \begin{align*}\tag{4} m_{\pi}(V_{pl} L_{{\!}_R})=m_{\pi}(k\cdot 10^{19}\mathrm{cm^{2}\cdot \sec^{-1}}); \end{align*} while $k$ has the following values: \begin{align*} k_{{\!}_{A}} = 3, 4, 5, 6; \quad k_{{\!}_{B}} = 11, 15, 21, 26, 30 \end{align*} We come to the following conclusion: the product $\boldsymbol{V_{pl} L_{{\!}_R}}$ is quantized.

3.4.4 We additionally state: the group of planets A is radically different from the group of planets B.

It is well known that the density of planets of group A is several times higher than the density of planets of group B (see Table 2). Table 6 shows that there is another fundamental difference—in the values of the quantized product $\bm{V_{pl} L_{{\!}_R}}$, corresponding to the planets of group A and the planets of group B.

3.5.1 It is necessary to answer the question—why is there a constant factor $10^{19}$ in all the data in Table 6? This is because the factor expresses the ratio between the mass of a graton $\bm{m_{\pi}}$ (that is, Planck mass $\boldsymbol{m_{\!_P}}$) and the mass of a proton $\bm{m_{p}}$. \begin{align*} \frac{m_{\pi}}{m_{p}} = \frac{2.1767\cdot10^{-5}}{1.6726 \cdot 10^{-24}} = 1.301\cdot 10^{19} \end{align*} \begin{align*}\tag{5} m_{\pi} \cong 1.3 \cdot 10^{19} m_{p} \end{align*}

3.5.2 Further we will examine only the group of planets A Let us introduce the relation between the masses of a graton and a proton in the data of Table 6; we obtain

Mercury: $m_{\pi}(3 \cdot 10^{19} \mathrm{cm^2 \cdot \sec^{-1}} ) = 1.3 m_{p}[3{(10^{19})}^{2} \mathrm{cm^2 \cdot \sec^{-1}}]$
Venus: $m_{\pi}(4 \cdot 10^{19} \mathrm{cm^2 \cdot \sec^{-1}}) = 1.3 m_{p}[4{(10^{19})}^{2} \mathrm{cm^2 \cdot \sec^{-1}}]$
Earth: $m_{\pi}(5 \cdot 10^{19} \mathrm{cm^2 \cdot \sec^{-1}}) = 1.3 m_{p}[5{(10^{19})}^{2} \mathrm{cm^2 \cdot \sec^{-1}}]$
Mars: $m_{\pi}(6 \cdot 10^{19} \mathrm{cm^2 \cdot \sec^{-1}}) = 1.3 m_{p}[6{(10^{19})}^{2} \mathrm{cm^2 \cdot \sec^{-1}}]$

A new constant factor has appeared—$\boldsymbol{{(10^{19})}^{2}}$. The same factor characterizes the ratio between the mass of the Sun and the mass of a graton (see §3.2.1) \begin{align*} \widetilde{M} / m_{\pi} \cong (10^{19})^{2} \end{align*}

3.6.1 Let us examine this factor. We present the following product \begin{align*}\tag{6} m_{\pi} \cdot m_{\pi} = (1.3\cdot 10^{19})^2 m^2_{p} \end{align*} Let us transform the obtained expression \begin{align*}\tag{7} m_{\pi}^2 = ( 10^{19})^2 (1.3\cdot m_{p})^{2} \end{align*}

3.6.2 According to Planck's formula (see §3.1.1), taking into account that $m_{\pi} \equiv m_{\!_P}$, we come to the following expressions \begin{align*}\tag{8} m_{\pi}^2 = \frac{\hbar c}{G} \end{align*} \begin{align*}\tag{9} (10^{19})^2 = \frac{\hbar c}{ (1.3 \cdot m_{p})^2 G} \end{align*}

3.7.1 By introducing formula (9) into the expressions given in §3.2.1 and §3.5.2, we obtain the following \begin{align*}\tag{10} \widetilde{M} = \frac{\hbar c}{ (1.3 \cdot m_{p})^2 G} m_{\pi} \end{align*}

The angular momentum of the unit for the group of planets A (units are not indicated on the left side):

Mercury: $1.3 m_{p}[3{(10^{19})}^{2}] = 3\left[\frac{\hbar c}{1.3 m_{p}G}\mathrm{\gram \cdot cm^2 \cdot \sec^{-1}}\right]$
Venus: $1.3 m_{p}[4{(10^{19})}^{2}] = 4\left[\frac{\hbar c}{1.3 m_{p}G}\mathrm{\gram \cdot cm^2 \cdot \sec^{-1}}\right]$
Earth: $1.3 m_{p}[5{(10^{19})}^{2}] = 5\left[\frac{\hbar c}{1.3 m_{p}G}\mathrm{\gram \cdot cm^2 \cdot \sec^{-1}}\right]$
Mars: $1.3 m_{p}[6{(10^{19})}^{2}] = 6\left[\frac{\hbar c}{1.3 m_{p}G}\mathrm{\gram \cdot cm^2 \cdot \sec^{-1}}\right]$
($m_{p}$ is the mass of a proton)

3.7.2 We indicate the following relations (formulas) \begin{align*} \widetilde{M}=(10^{19})^2 m_{\pi}; \quad (10^{19})^2 = \frac{\widetilde{M}}{m_{\pi}};\quad m_{p}(10^{19})^2=\widetilde{M} \frac{m_{p}}{m_{\pi}} \: \end{align*}

3.7.3 All angular momenta of the unit, which are considered in §3.3.4–§3.7.1, can be written as follows (without specifying the dimensions)

Mercury: $3\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Venus: $4\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Earth: $5\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Mars: $6\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Jupiter: $11\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Saturn: $15\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Uranus: $21\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Neptune: $26\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$
Pluto: $30\left(1.3\widetilde{M}\frac{m_{p}}{m_{\pi}}\right)$

3.7.4 Summarizing what has been said in this section, we come to the conclusion that the Solar System is such a collection of the star and the planets moving around this star, which is one whole cosmic object.

3.8.1 Suppose that in §3.3.4, §3.3.5 instead of $S =1$ we would take $S = 10^{8}$. In this case, formula (3) \begin{align*}\tag{11} (10^8 m_{\pi})V_{pl} L_{{\!}_R}, \end{align*} and also those expressions presented in §3.5.2 would change accordingly. In this case, the expressions given in §3.7.1 would have the following form

Mercury: $1.3 (10^8 m_{p}) [3{(10^{19})}^{2}] = 3\left[\frac{ 10^8 \hbar c}{1.3 m_{p}G} \mathrm{g \cdot cm^2 \cdot \sec ^{-1}}\right]$
Venus: $1.3 (10^8 m_{p}) [4{(10^{19})}^{2}] = 4\left[\frac{ 10^8 \hbar c}{1.3 m_{p}G} \mathrm{g \cdot cm^2 \cdot \sec ^{-1}}\right]$
Earth: $1.3 (10^8 m_{p}) [5{(10^{19})}^{2}] = 5\left[\frac{ 10^8 \hbar c}{1.3 m_{p}G} \mathrm{g \cdot cm^2 \cdot \sec ^{-1}}\right]$
Mars: $1.3 (10^8 m_{p}) [6{(10^{19})}^{2}] = 6\left[\frac{ 10^8 \hbar c}{1.3 m_{p}G} \mathrm{g \cdot cm^2 \cdot \sec ^{-1}}\right]$

3.8.2 We come to the following conclusion: for any value of the number $\bm{S}$ no fundamental changes occur—provided that $\bm{S < 10^{16}}$ (instead of the factor 1 in formula (3) another factor appears; in the example above—the factor $10^{8}$).

3.9.1 Results of parameter calculation $V_{pl} L_{{\!}_R}$ (of the angular momenta of the unit) corresponding to each planet (see Table 5) are quantities having the dimension $\si{\cm^2}\cdot \si{\sec^{-1}}$. Let us move on to other dimensions, for example, express the indicated results in $\si{\meter^2}\cdot \si{\sec^{-1}}$.

Because $1\si{\meter^2}=10^4 \si{\cm^2}$, then an additional factor $10^{-4}$ will appear. Therefore, the expressions given in §3.7.1 would take the form

Mercury: $1.3m_p\left[3 \frac{10^{19}}{10^4}10^{19}\right] = 3\left[\frac{\hbar c}{1.3\cdot 10^4m_{p}G} \mathrm{g \cdot m^2\cdot \sec^{-1}}\right]\:$
Venus: $1.3m_{p}\left[4 \frac{10^{19}}{10^4}10^{19}\right] = 4\left[\frac{\hbar c}{1.3\cdot 10^4m_{p}G} \mathrm{g \cdot m^2\cdot \sec^{-1}}\right]\:$
Earth: $1.3m_{p}\left[5 \frac{10^{19}}{10^4}10^{19}\right] = 5\left[\frac{\hbar c}{1.3\cdot 10^4m_{p}G} \mathrm{g \cdot m^2\cdot \sec^{-1}}\right]\:$
Mars: $1.3m_{p}\left[6 \frac{10^{19}}{10^4}10^{19}\right] = 6\left[\frac{\hbar c}{1.3\cdot 10^4m_{p}G} \mathrm{g \cdot m^2\cdot \sec^{-1}}\right]\:$

3.9.2 Specifying linear parameters in centimeters or meters, specifying time in seconds, means using in our calculations such systems of units that are introduced according to well-known international agreements. However, suppose the following (as an assumption):

  • all linear dimensions and distances are measured, for example, in yards;
  • The unit of time is taken to be the time required for photons to travel a path equal to the length of the Earth's equator.

This means that another additional factor would appear in our calculations, and not $10^{-4}$.

However, neither in the case described in §3.9.1 nor in the case described in §3.9.2 can additional factors lead to any fundamental changes in the record of calculation results. We have chosen the CGS system of units ($\si{\cm, \gram, \sec}$), so that certain (possible) additional factors are equal to 1.

4. A planetary atom in the Solar System

4.1.1 Consider the planetary model of a hydrogen atom—proposed by E. Rutherford and developed in depth by N. Bohr [6]. In accordance with this model, we will write down the parameters of an electron, which—as Bohr assumed—moves in the atom along one of the stationary (allowed) orbits; let us call them Bohr orbits. We present the well-known Bohr formula, which singles out the indicated trajectories (orbits) from all possible trajectories of an electron's motion in a hydrogen atom \begin{align*}\tag{12} m_{e}v_{n}R_{n}=n\frac{h}{2\pi} \end{align*} Here:

  • $m_{e}$ is the rest mass of an electron;
  • $v_{n}$ is the speed of movement of an electron around a proton;
  • $R_{n}$ is radius of the stationary (permitted) orbit;
  • $n$ is principal quantum number ($n = 1, 2, 3, 4, 5, 6 \dots$).
(In accordance with the Rutherford-Bohr model, we will consider only orbits (trajectories) in the form of a circle.)

4.1.2 Let $n = 1$; in this case, formula (12) will have the form

\begin{align*}\tag{13} m_{e}v_{{}_1}R_{1}=\frac{h}{2\pi} \end{align*} Here:
  • $v_{{}_1} = c/137$ ($c$ is the speed of light in vacuum);
  • $R_{1} \cong 5.29\cdot 10^{-9}\mathrm{cm}$ (radius of the first stationary orbit).
Let us transform formula (12) \begin{align*}\tag{14} v_nR_n=n\left( \frac{h}{2\pi} \frac{1}{m_e} \right) \end{align*}

4.2.1 We want to show the following.

In the Solar System there is a special group of planets; in this group of planets the unity of the main structural principles is manifested, according to which two natural objects are built, radically different in their scale and in their properties:

  • a physical object consisting of a proton (nucleus) and an electron, which—according to the Rutherford–Bohr model—moves around a proton (a hydrogen atom);
  • a physical object consisting of a star and a special group of planets moving around the star (we will call this special group of planets a planetary atom).

4.2.2 A hydrogen atom is the main element of the microcosm. The second object—a planetary atom in the Solar System—belongs to space, to the world of stars and galaxies.

4.2.3 A rigorous description of a hydrogen atom is possible only on the basis of quantum mechanics—wave or matrix. The Rutherford–Bohr model can be considered only as a first approximation, which gives a general representation of a hydrogen atom.

4.2.4 However, in the theoretical task that we have set—to show the unity of the main structural principles of constructing two such different natural objects—it is possible (and sufficient) to use an approximate representation of a hydrogen atom.

4.3.1 As is well known, the number of manifested energy levels in atoms of chemical elements is seven: $1, 2, 3, 4, 5, 6, 7$ (these numbers are the values of the first quantum number $n$).

4.3.2 Consequently, the planetary atom must consist of a group of such planets: Mercury, Venus, Earth and Mars. The following sequence of values of the product $V_{pl}L{\!_R}$ corresponds to these planets: $3, 4, 5, 6$ (see Section 3, §3.3.5, §3.3.6, as well as tables 5 and 6).

4.4.1 Let us return to formula (14) and perform the necessary calculations for $n=1$ \begin{align*} v_1 = \frac{c}{137} = 21.898 \cdot 10^7 \si{\cm}/\sec; \quad R_1 = 5.292 \cdot 10^{-9} \si{\cm} \end{align*}

4.4.2 It follows that \begin{align*} v_1 R_1 = \frac{h}{2\pi} \frac{1}{m_e} = (21.898 \cdot 10^7) \cdot (5.292 \cdot 10^{-9}) = 1.159 (\si{\cm}^2/\sec) \end{align*}

4.4.3 Let us move on to the planetary atom}. We will describe it with the following formula \begin{align*}\tag{15} V_{pl} L_{\!_R} = v_n R_n (\frac{3}{5} \frac{m_{\pi}}{m_p}) \end{align*} Here:

  • $m_\pi \equiv m_{\!_P}; \quad m_\pi / m_p = 1.301 \cdot 10^{19};$
  • $3/5$ is the coefficient taking into account the gravitational interaction between the planets.

4.4.4 The results of calculating the quantity $V_{pl} L_{\!_R}$ according to formula (15) are given in Table 7

Table 7: Calculation of the parameters of the planetary atom.
Planet Quantity $\boldsymbol{v_n R_n}$ for different values of $\boldsymbol{n}$ $\boldsymbol{(\si{\cm}^2/\sec)}$ Quantity $\boldsymbol{V_{pl}L{\!_R}}$ according to formula (15) $\boldsymbol{(10^{19} \si{\cm}^2/\sec)}$ Quantity $\boldsymbol{V_{pl}L{\!_R}}$ according to Table 5 $\boldsymbol{(10^{19} \si{\cm}^2/\sec)}$
$v_1 R_1$ 1.159
$v_2 R_2$ 2.318
Mercury $v_3 R_3$ 3.477 2.714 2.744
Venus $v_4 R_4$ 4.636 3.618 3.787
Earth $v_5 R_5$ 5.795 4.523 4.458
Mars $v_6 R_6$ 6.954 5.427 5.492

(We assume that the significant difference between the actual value of $V_{pl} L_R$ for Venus and the calculated value of $V_{pl} L_R$ is due to the fact that Venus revolves (moves around the Sun) in the direction opposite to the direction of revolution of most other planets.)

5. Conclusion

  • 1. Let us present the following data.
    • the minimum possible radius of a hydrogen atom (that is, the radius of the Bohr orbit at $n = 1$); we will denote this radius by $R_{\!_H}$ \begin{align*} R_{\!_H}=5.292\cdot 10^{-9} \mathrm{cm} \end{align*}
    • The ratio of Planck mass $m_{\!_P}$ and the mass of a proton $m_{p}$ (in this case: $m_{\!_P} \equiv m_{\pi}$—see §3.1.2); according to §3.5.1 \begin{align*} m_{\pi}=1.301\cdot 10^{19}m_{\!_p}\: \end{align*}
  • 2. Let us calculate the radius of the Sun, which we will denote by $R^{*}_{\odot}$. Let us calculate this radius using the following formula \begin{align*} R^{*}_{\odot}=\frac{m_{\pi}}{m_p} R_{\!_H} \end{align*} Next we get \begin{align*} R^{*}_{\odot}=1.301\cdot 10^{19} (5.292\cdot 10^{-9})=6.885 \cdot 10^{10} \si{\cm} \end{align*}
  • 3. Radius of the Sun (along the equator) according to NASA [3] \begin{align*} R_{\odot}=6.957 \cdot 10^{10} \si{\cm} \end{align*} Deviation of the calculated result from the observed data \begin{align*} \Delta = \frac{R_{\odot} - R^{*}_{\odot}}{R_{\odot}}=0.0103 \end{align*}
  • 4. The following should be noted:
    the dimensionless parameter $\boldsymbol{m_{\pi}/m_p}$, as well as the parameter $\boldsymbol{m_p / m_{\pi}}$, are special quantitative parameters of the Solar System.

References





Appendix

Content аnalysis of аrticle [1] (author of the article J.-A. Gu)

1. Three tables



Table 1: The conformity of the planetary orbits with the quantum energy levels.
(this table from article [1])
Planet Mercury Venus Earth Mars Jupiter Saturn Uranus Neptune
Mass ($10^{24}$kg) 0.330 4.87 5.97 0.642 1898 568 86.8 102
Orbital radius ($10^6$km)$^\ast$ 57.9 108.2 149.6 227.9 778.6 1433.5 2872.5 4495.1
Radius $n_i^2 r_0$ ($10^6$km)† 56.8 101.0 157.9 227.3 764.1 1420.9 2784.9 4603.7
Quantum number $n_i$ 3 4 5 6 11 15 21 27
Ground-state radius $r_0 = 6.315 \times 10^6$km
Fractional error ($\%$) $-1.84$ $-6.62$ $5.53$ $-0.245$ $-1.86$ $-0.880$ $-3.05$ $2.41$
Root-mean-square of the eight fractional errors: $\; 3.49\%$
$^\ast$ The semi-major axis, i.e., the average distance from a planet to the sun.
† The expectation value of the radius for an s-state energy level.




Table 2: Fragment of table 3 (from our article)
Planet Calculation of $\bm{L_r}$ (results are expressed in macro-units) Orbital radius $\boldsymbol{(10^{11} \si{\cm})}$ Orbital radius according to Titius-Bode calculation $\boldsymbol{(10^{11} \si{\cm})}$ Error %
1. Mercury ${8\phantom{+3 \cdot 2^15}=}{ \phantom{000}8}$ 57.9 57.9 0
2. Venus ${8+3 \cdot 2^1=}{ \phantom{00}14}$ 108.2 101.4 -6.28
3. Earth ${8+3 \cdot 2^2 =}{ \phantom{00}20}$ 149.6 144.8 -3.21
4. Mars ${8+3 \cdot 2^3 =}{ \phantom{00}32}$ 227.9 231.7 1.67
5. Jupiter ${8+3 \cdot 2^5 =}{ \phantom{0}104}$ 778.6 753.0 -3.29
6. Saturn ${8+3 \cdot 2^6 =}{ \phantom{0}200}$ 1433.5 1448.0 1.01
7. (Uranus) ${8+3 \cdot 2^7=}{ \phantom{0}392}$ 2872.5 2838.1 -1.20
8. (Neptune) 4495.1
9. (Pluto) 5906.4
(The Titius-Bode quantization law is applicable at a distance of the planet from the Sun up to $20~\mathrm{AU}$.)



Table 3: Comparison of results of different calculations
Planet Orbital radius $\boldsymbol{(10^{11} \si{\cm})}$ Orbital radius according to the formula $\boldsymbol{n_i^2 r_0}$ $\boldsymbol{(10^{11} \si{\cm})}$ Error % Orbital radius according to Titius-Bode calculation $\boldsymbol{(10^{11} \si{\cm})}$ Error %
Mercury 57.9 56.8 -1.84 57.9 0
Venus 108.2 101.0 -6.62 101.4 -6.28
Earth 149.6 157.9 5.53 144.8 -3.21
Mars 227.9 227.3 -0.245 231.7 1.67
Jupiter 778.6 764.1 -1.86 753.0 -3.29
Saturn 1433.5 1420.9 -0.880 1448.0 1.01
(Uranus) 2872.5 2784.9 -3.05 2838.1 -1.20
(Neptune) 4495.1 4603.7 2.41
(Pluto)

Root mean square errors.

  • For the first four planets (1, 2, 3, 4)
    • According to the quantization law (formula) $n_i^2 r_0$: 4.412%
    • According to the Titius-Bode quantization law (formula): 3.624%
  • For the seven planets (from 1 to 7)
    • According to the quantization law (formula) $n_i^2 r_0$: 3.613%
    • According to the Titius-Bode quantization law (formula): 3.066%

2. Two approaches to calculating the orbital radius of the planets

  • A. A comparison of the calculation results in Table 3 shows that calculations according to the law (formula) $2^1, 2^2, 2^3, \dots$ give significantly more accurate values of the orbital radii than calculations according to the law (formula) $n_i^2 r_0$.
  • B. The law (formula) of quantization of orbital radii $\boldsymbol{2^1, 2^2, 2^3, \dots}$ has no connection with the energy levels of the atom.
  • C. According to physical chemistry, the number of manifested energy levels in atoms of chemical elements does not exceed seven ($1, 2, 3, 4, 5, 6, 7$). In nature, chemical elements with atoms manifesting energy levels of $\boldsymbol{11, 15, 21, 27}$ are unknown.
  • D. The above means that the statements of the author of article [1]:
    • in the title of article [1] (The solar system mimics a hydrogen atom);
    • in the title of table 1 (Correspondence of planetary orbits to quantum energy levels);
    • in the Abstract;
    • in other places in the text of the article;
  • do not have the necessary justification.

P.S.

The International Astronomical Union changed Pluto's planetary status in August 2006. Pluto is now the largest (of all known) minor planet in the Solar System (not by mass, but by size). However—for the purposes of our article—we left Pluto as the ninth planet.

References for Appendix

  • [1] Gu, J.-A The solar system mimics a hydrogen atom 2014. https://arxiv.org/abs/1405.1654.